/**
 * @file permutation-of-multisets.cpp
 * @author prakash (prakashsellathurai@gmail.com)
 * @brief
 * @version 0.1
 * @date 2021-08-02
 *
 * @copyright Copyright (c) 2021
 *
 */

#include <algorithm>
#include <iostream>
#include <map>

#define NMAX 10000
using namespace std;

/**
 * @brief print the permutation of unique multisets
 *
 * @param arr
 * @param n
 */
void print_perm(int *arr, int n) {
  cout << "{";
  for (int i = 0; i < n; i++) {
    cout << arr[i];
    if (i < n - 1) {
      cout << ", ";
    }
  }
  cout << "}" << endl;
}
/**
 * @brief Genrate unique combinations
 *  if arr of n elements has n! permutations
 *  then the number of unique combinations is
 *  n!/(n-k)!
 *  with length m
 * @param arr
 * @param c
 * @param start
 * @param end
 * @param i
 * @param n
 */
void combination_of_multisets(int *arr, int c[], int k, map<int, int> counter,
                              int n) {

  if (k == n) {
    print_perm(arr, n);
    return;
  }

  for (auto count : counter) {
    if (count.second > 0) {
      arr[k] = count.first;
      counter[count.first]--;
      combination_of_multisets(arr, c, k + 1, counter, n);
      counter[count.first]++;
    }
  }
}

void generate_combination(int *arr, int n) {
  map<int, int> counter;
  int k;
  int c[NMAX];

  for (int i = 0; i < n; i++) {
    if (!counter[arr[i]]) {
      counter[arr[i]] = 0;
    }
    counter[arr[i]]++;
  }

  combination_of_multisets(arr, c, 0, counter, n);
}

/////////////////////////////////////////////////////////////////////////


/**
 * @brief cleverly finds next permutation
 * 
 * @param arr 
 * @param n 
 * @return true 
 * @return false 
 */
bool next_permutation(int *arr, int n) {
  int i,j;
  for (i = n - 2; i >= 0; i--) {
    if (arr[i] < arr[i + 1]) {
      break;
    }
  }
  if (i < 0) {
    reverse(arr, arr + n);
    return false;
  } else {
    for (j = n - 1; j > i; j--) {
      if (arr[j] > arr[i]) {
        break;
      }
    }
            swap(arr[i], arr[j]);
    reverse(arr + i + 1, arr + n);
    return true;
  }
}
/**
 * @brief

 Besides backtracking, you may also solve it using Next Permutation: computing
 the next permutation and add it to the result until it becomes the original
 array
 * https://stackoverflow.com/a/11425168/8336491
 * @param arr
 * @param n
 */
void alternate_approach(int *arr, int n) {
  sort(arr, arr + n);
  do {
    print_perm(arr, n);
  } while (next_permutation(arr, n));
}

int main(int argc, char const *argv[]) {
  int arr[] = {1, 1, 2, 2};
  int n = sizeof(arr) / sizeof(arr[0]);
  generate_combination(arr, n);
  cout << "alternate approach" << endl;
  alternate_approach(arr, n);
  return 0;
}