# 0622-design-circular-queue


Try it on <a href='https://leetcode.com/problems/0622-design-circular-queue'>leetcode</a>

## Description
<div class="description">
<p>Design your implementation of the circular queue. The circular queue is a linear data structure in which the operations are performed based on FIFO (First In First Out) principle, and the last position is connected back to the first position to make a circle. It is also called &quot;Ring Buffer&quot;.</p>

<p>One of the benefits of the circular queue is that we can make use of the spaces in front of the queue. In a normal queue, once the queue becomes full, we cannot insert the next element even if there is a space in front of the queue. But using the circular queue, we can use the space to store new values.</p>

<p>Implement the <code>MyCircularQueue</code> class:</p>

<ul>
	<li><code>MyCircularQueue(k)</code> Initializes the object with the size of the queue to be <code>k</code>.</li>
	<li><code>int Front()</code> Gets the front item from the queue. If the queue is empty, return <code>-1</code>.</li>
	<li><code>int Rear()</code> Gets the last item from the queue. If the queue is empty, return <code>-1</code>.</li>
	<li><code>boolean enQueue(int value)</code> Inserts an element into the circular queue. Return <code>true</code> if the operation is successful.</li>
	<li><code>boolean deQueue()</code> Deletes an element from the circular queue. Return <code>true</code> if the operation is successful.</li>
	<li><code>boolean isEmpty()</code> Checks whether the circular queue is empty or not.</li>
	<li><code>boolean isFull()</code> Checks whether the circular queue is full or not.</li>
</ul>

<p>You must solve the problem without using the built-in queue data structure in your programming language.&nbsp;</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input</strong>
[&quot;MyCircularQueue&quot;, &quot;enQueue&quot;, &quot;enQueue&quot;, &quot;enQueue&quot;, &quot;enQueue&quot;, &quot;Rear&quot;, &quot;isFull&quot;, &quot;deQueue&quot;, &quot;enQueue&quot;, &quot;Rear&quot;]
[[3], [1], [2], [3], [4], [], [], [], [4], []]
<strong>Output</strong>
[null, true, true, true, false, 3, true, true, true, 4]

<strong>Explanation</strong>
MyCircularQueue myCircularQueue = new MyCircularQueue(3);
myCircularQueue.enQueue(1); // return True
myCircularQueue.enQueue(2); // return True
myCircularQueue.enQueue(3); // return True
myCircularQueue.enQueue(4); // return False
myCircularQueue.Rear();     // return 3
myCircularQueue.isFull();   // return True
myCircularQueue.deQueue();  // return True
myCircularQueue.enQueue(4); // return True
myCircularQueue.Rear();     // return 4
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= k &lt;= 1000</code></li>
	<li><code>0 &lt;= value &lt;= 1000</code></li>
	<li>At most <code>3000</code> calls will be made to&nbsp;<code>enQueue</code>, <code>deQueue</code>,&nbsp;<code>Front</code>,&nbsp;<code>Rear</code>,&nbsp;<code>isEmpty</code>, and&nbsp;<code>isFull</code>.</li>
</ul>

</div>

## Solution(Python)
```Python
class MyCircularQueue:

    def __init__(self, k: int):
        self.front = 0
        self.arr = [-1] * k 
        self.capsize = k 
        self.size = 0

    def enQueue(self, value: int) -> bool:
        if self.size >= self.capsize:
            return False
        rear = (self.front + self.size) % self.capsize
        self.arr[rear] = value
        self.size += 1
        return True

    def deQueue(self) -> bool:
        if self.size == 0:
            return False
        res = self.arr[self.front]
        self.front = (self.front + 1) % self.capsize
        self.size -= 1
        return True

    def Front(self) -> int:
        if self.size == 0:
            return -1
        return self.arr[self.front]

    def Rear(self) -> int:
        if self.size == 0:
            return -1
        rear = (self.front + self.size - 1) % self.capsize
        return self.arr[rear]

    def isEmpty(self) -> bool:
        return self.size == 0

    def isFull(self) -> bool:
        return self.size == self.capsize
        


# Your MyCircularQueue object will be instantiated and called as such:
# obj = MyCircularQueue(k)
# param_1 = obj.enQueue(value)
# param_2 = obj.deQueue()
# param_3 = obj.Front()
# param_4 = obj.Rear()
# param_5 = obj.isEmpty()
# param_6 = obj.isFull()
```