# 0729-my-calendar-i Try it on leetcode ## Description

You are implementing a program to use as your calendar. We can add a new event if adding the event will not cause a double booking.

A double booking happens when two events have some non-empty intersection (i.e., some moment is common to both events.).

The event can be represented as a pair of integers startTime and endTime that represents a booking on the half-open interval [startTime, endTime), the range of real numbers x such that startTime <= x < endTime.

Implement the MyCalendar class:

 

Example 1:

Input
["MyCalendar", "book", "book", "book"]
[[], [10, 20], [15, 25], [20, 30]]
Output
[null, true, false, true]

Explanation
MyCalendar myCalendar = new MyCalendar();
myCalendar.book(10, 20); // return True
myCalendar.book(15, 25); // return False, It can not be booked because time 15 is already booked by another event.
myCalendar.book(20, 30); // return True, The event can be booked, as the first event takes every time less than 20, but not including 20.

 

Constraints:

## Solution(Python) ```Python from sortedcontainers import SortedList class MyCalendar: def __init__(self): self.Naivecalendar = [] self.sortedCalnder = SortedList() def book(self, start, end): return self.sorting(start, end) # Time Complexity: O(N**2) # Spac complexity: O(N) def naive(self, start, end): for s, e in self.Naivecalendar: if s < end and start < e: return False self.Naivecalendar.append((start, end)) return True # Time Complexity: O(NlogN) # Spac complexity: O(N) def sorting(self, start, end): idx = self.sortedCalnder.bisect_right((start, end)) if (idx > 0 and self.sortedCalnder[idx-1][1] > start) or (idx < len(self.sortedCalnder) and self.sortedCalnder[idx][0] < end): return False self.sortedCalnder.add((start, end)) return True # Your MyCalendar object will be instantiated and called as such: # obj = MyCalendar() # param_1 = obj.book(startTime,endTime) ```