# 191-number-of-1-bits Try it on leetcode ## Description

Write a function that takes an unsigned integer and returns the number of '1' bits it has (also known as the Hamming weight).

Note:

 

Example 1:

Input: n = 00000000000000000000000000001011
Output: 3
Explanation: The input binary string 00000000000000000000000000001011 has a total of three '1' bits.

Example 2:

Input: n = 00000000000000000000000010000000
Output: 1
Explanation: The input binary string 00000000000000000000000010000000 has a total of one '1' bit.

Example 3:

Input: n = 11111111111111111111111111111101
Output: 31
Explanation: The input binary string 11111111111111111111111111111101 has a total of thirty one '1' bits.

 

Constraints:

 

Follow up: If this function is called many times, how would you optimize it?
## Solution(Python) ```Python class Solution: def hammingWeight(self, n: int) -> int: return self.bitmanipulation(n) # Time Complexity: O(2^logn) # Space Complexity: O(logn) def bruteforce(self, n): n = bin(n) def recur(n): if not n: return 0 return recur(n[1:]) + 1 if n[0] == "1" else recur(n[1:]) return recur(n) # Time Complexity: O(log(n)) # Space Complexity: O(logn) def naive(self, n): return bin(n).count("1") # Time Complexity: O(log(n)) # Space Complexity: O(1) def bitmanipulation(self, n): cnt = 0 while n: n &= n - 1 cnt += 1 return cnt ```