# 429-n-ary-tree-level-order-traversal Try it on leetcode ## Description

Given an n-ary tree, return the level order traversal of its nodes' values.

Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples).

 

Example 1:

Input: root = [1,null,3,2,4,null,5,6]
Output: [[1],[3,2,4],[5,6]]

Example 2:

Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]
Output: [[1],[2,3,4,5],[6,7,8,9,10],[11,12,13],[14]]

 

Constraints:

## Solution(Python) ```Python """ # Definition for a Node. class Node: def __init__(self, val=None, children=None): self.val = val self.children = children """ class Solution: def levelOrder(self, root: 'Node') -> List[List[int]]: if not root: return [] q = deque([root]) res = [] while q: n = len(q) cur_level = [] for _ in range(n): node = q.popleft() if node: cur_level.append(node.val) for child in node.children: q.append(child) res.append(cur_level) return res ```