# 981-time-based-key-value-store


Try it on <a href='https://leetcode.com/problems/981-time-based-key-value-store'>leetcode</a>

## Description
<div class="description">
<div><p>Design a time-based key-value data structure that can store multiple values for the same key at different time stamps and retrieve the key's value at a certain timestamp.</p>

<p>Implement the <code>TimeMap</code> class:</p>

<ul>
	<li><code>TimeMap()</code> Initializes the object of the data structure.</li>
	<li><code>void set(String key, String value, int timestamp)</code> Stores the key <code>key</code> with the value <code>value </code>at the given time <code>timestamp</code>.</li>
	<li><code>String get(String key, int timestamp)</code> Returns a value such that <code>set</code> was called previously, with <code>timestamp_prev &lt;= timestamp</code>. If there are multiple such values, it returns the value associated with the largest <code>timestamp_prev</code>. If there are no values, it returns <code>""</code>.</li>
</ul>

<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>

<pre><strong>Input</strong>
["TimeMap", "set", "get", "get", "set", "get", "get"]
[[], ["foo", "bar", 1], ["foo", 1], ["foo", 3], ["foo", "bar2", 4], ["foo", 4], ["foo", 5]]
<strong>Output</strong>
[null, null, "bar", "bar", null, "bar2", "bar2"]

<strong>Explanation</strong>
TimeMap timeMap = new TimeMap();
timeMap.set("foo", "bar", 1);  // store the key "foo" and value "bar" along with timestamp = 1.
timeMap.get("foo", 1);         // return "bar"
timeMap.get("foo", 3);         // return "bar", since there is no value corresponding to foo at timestamp 3 and timestamp 2, then the only value is at timestamp 1 is "bar".
timeMap.set("foo", "bar2", 4); // store the key "foo" and value "bar2" along with timestamp = 4.
timeMap.get("foo", 4);         // return "bar2"
timeMap.get("foo", 5);         // return "bar2"
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= key.length, value.length &lt;= 100</code></li>
	<li><code>key</code> and <code>value</code> consist of lowercase English letters and digits.</li>
	<li><code>1 &lt;= timestamp &lt;= 10<sup>7</sup></code></li>
	<li>All the timestamps <code>timestamp</code> of <code>set</code> are strictly increasing.</li>
	<li>At most <code>2 * 10<sup>5</sup></code> calls will be made to <code>set</code> and <code>get</code>.</li>
</ul>
</div>
</div>

## Solution(Python)
```Python
class TimeMap:
    def __init__(self):
        self.times = collections.defaultdict(list)
        self.values = collections.defaultdict(list)

    def set(self, key: str, value: str, timestamp: int) -> None:
        self.times[key].append(timestamp)
        self.values[key].append(value)

    def get(self, key: str, timestamp: int) -> str:
        i = bisect.bisect(self.times[key], timestamp)
        return self.values[key][i - 1] if i else ""

```