# minimum-absolute-difference Try it on leetcode ## Description

Given an array of distinct integers arr, find all pairs of elements with the minimum absolute difference of any two elements. 

Return a list of pairs in ascending order(with respect to pairs), each pair [a, b] follows

 

Example 1:

Input: arr = [4,2,1,3]
Output: [[1,2],[2,3],[3,4]]
Explanation: The minimum absolute difference is 1. List all pairs with difference equal to 1 in ascending order.

Example 2:

Input: arr = [1,3,6,10,15]
Output: [[1,3]]

Example 3:

Input: arr = [3,8,-10,23,19,-4,-14,27]
Output: [[-14,-10],[19,23],[23,27]]

 

Constraints:

## Solution(Python) ```Python class Solution: def minimumAbsDifference(self, arr: List[int]) -> List[List[int]]: arr.sort() res = [] min_diff = float("INF") for i in range(len(arr) - 1): diff = arr[i + 1] - arr[i] if diff == min_diff: res.append([arr[i], arr[i + 1]]) elif diff < min_diff: min_diff = diff res = [[arr[i], arr[i + 1]]] return res ```