0991-broken-calculator¶
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Description¶
There is a broken calculator that has the integer startValue on its display initially. In one operation, you can:
- multiply the number on display by
2, or - subtract
1from the number on display.
Given two integers startValue and target, return the minimum number of operations needed to display target on the calculator.
Example 1:
Input: startValue = 2, target = 3
Output: 2
Explanation: Use double operation and then decrement operation {2 -> 4 -> 3}.
Example 2:
Input: startValue = 5, target = 8
Output: 2
Explanation: Use decrement and then double {5 -> 4 -> 8}.
Example 3:
Input: startValue = 3, target = 10
Output: 3
Explanation: Use double, decrement and double {3 -> 6 -> 5 -> 10}.
Constraints:
1 <= startValue, target <= 109
Solution(Python)¶
class Solution:
def brokenCalc(self, startValue: int, target: int) -> int:
cnt = 0
while target > startValue:
if startValue == target:
break
if not target % 2:
target//=2
else:
target+=1
cnt+=1
return cnt + startValue -target