412-fizz-buzz¶

Description¶

Given an integer n, return a string array answer (1-indexed) where:

answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
answer[i] == "Fizz" if i is divisible by 3.
answer[i] == "Buzz" if i is divisible by 5.
answer[i] == i (as a string) if none of the above conditions are true.

Example 1:

Input: n = 3
Output: ["1","2","Fizz"]

Example 2:

Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]

Example 3:

Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

Constraints:

1 <= n <= 10⁴

Solution(Python)¶

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        res = []
        for i in range(1,n+1):
            if i % 3 ==0 and  i%5 == 0:
                res.append("FizzBuzz")
            elif i % 3 ==0 :
                res.append("Fizz")
            elif i % 5 ==0 :
                res.append("Buzz")
            else:
                res.append(str(i))
        return res
                