916-word-subsets¶
Try it on leetcode
Description¶
You are given two string arrays words1 and words2.
A string b is a subset of string a if every letter in b occurs in a including multiplicity.
- For example,
"wrr"is a subset of"warrior"but is not a subset of"world".
A string a from words1 is universal if for every string b in words2, b is a subset of a.
Return an array of all the universal strings in words1. You may return the answer in any order.
Example 1:
Input: words1 = ["amazon","apple","facebook","google","leetcode"], words2 = ["e","o"] Output: ["facebook","google","leetcode"]
Example 2:
Input: words1 = ["amazon","apple","facebook","google","leetcode"], words2 = ["l","e"] Output: ["apple","google","leetcode"]
Constraints:
1 <= words1.length, words2.length <= 1041 <= words1[i].length, words2[i].length <= 10words1[i]andwords2[i]consist only of lowercase English letters.- All the strings of
words1are unique.
Solution(Python)¶
class Solution(object):
def wordSubsets(self, A, B):
def count(word):
ans = [0] * 26
for letter in word:
ans[ord(letter) - ord('a')] += 1
return ans
bmax = [0] * 26
for b in B:
for i, c in enumerate(count(b)):
bmax[i] = max(bmax[i], c)
ans = []
for a in A:
if all(x >= y for x, y in zip(count(a), bmax)):
ans.append(a)
return ans