1009-complement-of-base-10-integer¶
Try it on leetcode
Description¶
The complement of an integer is the integer you get when you flip all the 0
's to 1
's and all the 1
's to 0
's in its binary representation.
- For example, The integer
5
is"101"
in binary and its complement is"010"
which is the integer2
.
Given an integer n
, return its complement.
Example 1:
Input: n = 5 Output: 2 Explanation: 5 is "101" in binary, with complement "010" in binary, which is 2 in base-10.
Example 2:
Input: n = 7 Output: 0 Explanation: 7 is "111" in binary, with complement "000" in binary, which is 0 in base-10.
Example 3:
Input: n = 10 Output: 5 Explanation: 10 is "1010" in binary, with complement "0101" in binary, which is 5 in base-10.
Constraints:
0 <= n < 109
Note: This question is the same as 476: https://leetcode.com/problems/number-complement/
Solution(Python)¶
class Solution:
# Question: given n flip al it's bits
# For Example: for "101" return "010"
#
# Draft:
# we needed a bit manipulation technique that flips the
# bits
# 1.and - not useful here
# 2.Or - not useful here
# 3. >> / << - not useful here
#
# 4.xor - 1^0 = 1 1^1 = 0 (i.e xor with 1's flips the bits)
# 5.~ = one' complement
#
# which gives us Xor and complement,
# 1.xor:
# we can use a mask lets say 11111 with bit length same as n
# constructing the mask of length log(n) can be done in loop
# by formula mask = (2*mask+1) and then xoring with the n
#
# 2.complement: works by invering each bit of the input
#
#
# Time Complexity: O(log(n))
# Space Complexity: O(1)
def bitwiseComplement(self, n: int) -> int:
mask = 1
while mask < n:
mask = 2 * mask + 1
return mask ^ n