104-maximum-depth-of-binary-tree

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Description

Solution(Python)

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def maxDepth(self, root: Optional[TreeNode]) -> int:
        return self.morrisinorder(root)

    # Time Complexity: O(n)
    # Space Complexity: O(n)
    def dfs(self, root: Optional[TreeNode]) -> int:
        if not root:
            return 0
        left = self.maxDepth(root.left)
        right = self.maxDepth(root.right)
        return max(left, right) + 1

    # Time Complexity: O(n)
    # Space Complexity: O(1)
    def morrisinorder(self, root: Optional[TreeNode]) -> int:
        if not root:
            return 0
        depth = 1
        maxdepth = depth
        while root:
            if not root.left:
                maxdepth = max(maxdepth, depth)
                root = root.right
            else:
                pre = root.left
                preDepth = 1

                while pre.right and pre.right is not root:
                    preDepth += 1
                    pre = pre.right

                if pre.right is root:
                    pre.right = None
                    depth -= preDepth + 1
                    maxdepth = max(maxdepth, depth)
                    root = root.right
                else:
                    pre.right = root
                    root = root.left
            depth += 1
        return maxdepth