1510-stone-game-iv¶
Try it on leetcode
Description¶
Alice and Bob take turns playing a game, with Alice starting first.
Initially, there are n
stones in a pile. On each player's turn, that player makes a move consisting of removing any non-zero square number of stones in the pile.
Also, if a player cannot make a move, he/she loses the game.
Given a positive integer n
, return true
if and only if Alice wins the game otherwise return false
, assuming both players play optimally.
Example 1:
Input: n = 1 Output: true Explanation: Alice can remove 1 stone winning the game because Bob doesn't have any moves.
Example 2:
Input: n = 2 Output: false Explanation: Alice can only remove 1 stone, after that Bob removes the last one winning the game (2 -> 1 -> 0).
Example 3:
Input: n = 4 Output: true Explanation: n is already a perfect square, Alice can win with one move, removing 4 stones (4 -> 0).
Constraints:
1 <= n <= 105
Solution(Python)¶
class Solution:
# @cache
# def winnerSquareGame(self, n: int) -> bool:
# if n == 0:
# return False
# for i in range(1,int(pow(n,0.5)+1)):
# if not self.winnerSquareGame(n-i*i):
# return True
# return False
# Time Complexity : N^(1+1/2)
# Space Complexity: N
def winnerSquareGame(self, n: int) -> bool:
dp = [False] * (n + 1)
for i in range(1, n + 1):
for j in range(1, int(pow(i, 0.5) + 1)):
if not dp[i - j * j]:
dp[i] = True
break
return dp[n]