916-word-subsets¶
Try it on leetcode
Description¶
You are given two string arrays words1
and words2
.
A string b
is a subset of string a
if every letter in b
occurs in a
including multiplicity.
- For example,
"wrr"
is a subset of"warrior"
but is not a subset of"world"
.
A string a
from words1
is universal if for every string b
in words2
, b
is a subset of a
.
Return an array of all the universal strings in words1
. You may return the answer in any order.
Example 1:
Input: words1 = ["amazon","apple","facebook","google","leetcode"], words2 = ["e","o"] Output: ["facebook","google","leetcode"]
Example 2:
Input: words1 = ["amazon","apple","facebook","google","leetcode"], words2 = ["l","e"] Output: ["apple","google","leetcode"]
Constraints:
1 <= words1.length, words2.length <= 104
1 <= words1[i].length, words2[i].length <= 10
words1[i]
andwords2[i]
consist only of lowercase English letters.- All the strings of
words1
are unique.
Solution(Python)¶
class Solution(object):
def wordSubsets(self, A, B):
def count(word):
ans = [0] * 26
for letter in word:
ans[ord(letter) - ord('a')] += 1
return ans
bmax = [0] * 26
for b in B:
for i, c in enumerate(count(b)):
bmax[i] = max(bmax[i], c)
ans = []
for a in A:
if all(x >= y for x, y in zip(count(a), bmax)):
ans.append(a)
return ans