95-unique-binary-search-trees-ii¶
Try it on leetcode
Description¶
Given an integer n
, return all the structurally unique BST's (binary search trees), which has exactly n
nodes of unique values from 1
to n
. Return the answer in any order.
Example 1:

Input: n = 3 Output: [[1,null,2,null,3],[1,null,3,2],[2,1,3],[3,1,null,null,2],[3,2,null,1]]
Example 2:
Input: n = 1 Output: [[1]]
Constraints:
1 <= n <= 8
Solution(Python)¶
class Solution:
def generateTrees(self, n: int) -> List[Optional[TreeNode]]:
@lru_cache(None)
def dfs(left, right):
if left > right:
return [None]
if left == right:
return [TreeNode(left)]
ans = []
for root in range(left, right + 1):
leftNodes = dfs(left, root - 1)
rightNodes = dfs(root + 1, right)
for leftNode in leftNodes:
for rightNode in rightNodes:
rootNode = TreeNode(root, leftNode, rightNode)
ans.append(rootNode)
return ans
return dfs(1, n)