98-validate-binary-search-tree¶
Try it on leetcode
Description¶
Given the root
of a binary tree, determine if it is a valid binary search tree (BST).
A valid BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
Example 1:

Input: root = [2,1,3] Output: true
Example 2:

Input: root = [5,1,4,null,null,3,6] Output: false Explanation: The root node's value is 5 but its right child's value is 4.
Constraints:
- The number of nodes in the tree is in the range
[1, 104]
. -231 <= Node.val <= 231 - 1
Solution(Python)¶
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def isValidBST(self, root: Optional[TreeNode]) -> bool:
return self.naive(root)
# Time Complexity: O(n)
# Space Complexity: O(h)
def naive(self, root: Optional[TreeNode]) -> bool:
def inorder(node):
if node:
inorder(node.left)
res.append(node.val)
inorder(node.right)
res = []
inorder(root)
if len(res) == 2:
return res[0] < res[1]
for i in range(1, len(res) - 1):
if not (res[i - 1] < res[i] < res[i + 1]):
return False
return True