find-all-numbers-disappeared-in-an-array¶
Try it on leetcode
Description¶
Given an array nums
of n
integers where nums[i]
is in the range [1, n]
, return an array of all the integers in the range [1, n]
that do not appear in nums
.
Example 1:
Input: nums = [4,3,2,7,8,2,3,1] Output: [5,6]
Example 2:
Input: nums = [1,1] Output: [2]
Constraints:
n == nums.length
1 <= n <= 105
1 <= nums[i] <= n
Follow up: Could you do it without extra space and in O(n)
runtime? You may assume the returned list does not count as extra space.
Solution(Python)¶
class Solution:
def findDisappearedNumbers(self, nums: List[int]) -> List[int]:
integers = set(i+1 for i in range(len(nums)))
for num in nums:
if num in integers:
integers.remove(num)
return list(integers)