0151-reverse-words-in-a-string¶
Try it on leetcode
Description¶
Given an input string s, reverse the order of the words.
A word is defined as a sequence of non-space characters. The words in s will be separated by at least one space.
Return a string of the words in reverse order concatenated by a single space.
Note that s may contain leading or trailing spaces or multiple spaces between two words. The returned string should only have a single space separating the words. Do not include any extra spaces.
Example 1:
Input: s = "the sky is blue" Output: "blue is sky the"
Example 2:
Input: s = " hello world " Output: "world hello" Explanation: Your reversed string should not contain leading or trailing spaces.
Example 3:
Input: s = "a good example" Output: "example good a" Explanation: You need to reduce multiple spaces between two words to a single space in the reversed string.
Constraints:
1 <= s.length <= 104scontains English letters (upper-case and lower-case), digits, and spaces' '.- There is at least one word in
s.
Follow-up: If the string data type is mutable in your language, can you solve it in-place with O(1) extra space?
Solution(Python)¶
class Solution:
def reverseWords(self, s: str) -> str:
# reverse the s
# us etwo piinter to reverse the individual words
def reverse(s, i , j):
while i < j:
s[i], s[j] = s[j],s[i]
i += 1
j-=1
s = list(s)
n = len(s)
reverse(s,0, n -1)
i = 0
res = []
while i < n:
j = i
while j < n and s[j] != ' ':
j+=1
reverse(s, i, j-1)
word = "".join(s[i:j])
if word:
res.append(word)
while j< n and s[j] == ' ':
j+=1
i = j
return " ".join(res)