0383-ransom-note

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Description

Given two strings ransomNote and magazine, return true if ransomNote can be constructed by using the letters from magazine and false otherwise.

Each letter in magazine can only be used once in ransomNote.

 

Example 1:

Input: ransomNote = "a", magazine = "b"
Output: false

Example 2:

Input: ransomNote = "aa", magazine = "ab"
Output: false

Example 3:

Input: ransomNote = "aa", magazine = "aab"
Output: true

 

Constraints:

  • 1 <= ransomNote.length, magazine.length <= 105
  • ransomNote and magazine consist of lowercase English letters.

Solution(Python)

from collections import Counter
class Solution:
    def canConstruct(self, ransomNote: str, magazine: str) -> bool:
        # ansomNote = "aa", magazine = "ab" False
        #
        # ransomNote = "aa", magazine = "aab" True
        # cccccccc
        if len(ransomNote) > len(magazine): return False

        magazine_set = Counter(magazine)
        for c in ransomNote:
            if magazine_set[c] == 0:
                return False
            magazine_set[c] -= 1

        return True