0202-happy-number¶
Try it on leetcode
Description¶
Write an algorithm to determine if a number n is happy.
A happy number is a number defined by the following process:
- Starting with any positive integer, replace the number by the sum of the squares of its digits.
- Repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1.
- Those numbers for which this process ends in 1 are happy.
Return true if n is a happy number, and false if not.
Example 1:
Input: n = 19 Output: true Explanation: 12 + 92 = 82 82 + 22 = 68 62 + 82 = 100 12 + 02 + 02 = 1
Example 2:
Input: n = 2 Output: false
Constraints:
1 <= n <= 231 - 1
Solution(Python)¶
class Solution:
def isHappy(self, n: int) -> bool:
# base 10 converges to 1
#
# case 1 converge to 1
# case 2 cycle
# case 3 infinity
#
def get_next(num):
total_sum = 0
while num > 0:
num,digit = divmod(num, 10)
total_sum += digit **2
return total_sum
slow = n
fast = get_next(n)
while slow!= 1 and slow != fast:
slow = get_next(slow)
fast = get_next(get_next(fast))
return fast == 1