93-restore-ip-addresses¶
Try it on leetcode
Description¶
A valid IP address consists of exactly four integers separated by single dots. Each integer is between 0
and 255
(inclusive) and cannot have leading zeros.
- For example,
"0.1.2.201"
and"192.168.1.1"
are valid IP addresses, but"0.011.255.245"
,"192.168.1.312"
and"192.168@1.1"
are invalid IP addresses.
Given a string s
containing only digits, return all possible valid IP addresses that can be formed by inserting dots into s
. You are not allowed to reorder or remove any digits in s
. You may return the valid IP addresses in any order.
Example 1:
Input: s = "25525511135" Output: ["255.255.11.135","255.255.111.35"]
Example 2:
Input: s = "0000" Output: ["0.0.0.0"]
Example 3:
Input: s = "101023" Output: ["1.0.10.23","1.0.102.3","10.1.0.23","10.10.2.3","101.0.2.3"]
Constraints:
0 <= s.length <= 20
s
consists of digits only.
Solution(Python)¶
class Solution:
def restoreIpAddresses(self, s: str) -> List[str]:
res = []
def backtrack(s, count, path, res):
if count == 4:
if not s:
res.append(path[:-1])
return
for i in range(1, 4):
if i > len(s):
continue
if i > 1 and s[0] == "0":
continue
if i > 2 and int(s[:3]) > 255:
continue
backtrack(s[i:], count + 1, path + s[:i] + ".", res)
backtrack(s, 0, "", res)
return res